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The latest posts from @chrismuellerpgh First, solve one of the equations for x. It doesn't matter which one. 2x +4 = −4y 2x = −4 −4y x = − 2 − 2y Next, plug this equation for x into the other equation 7x +6y + 11 = 0 7(−2 −2y) + 6y +11 = 0 −14− 14y + 6y + 11 = 0 −14− 8y +11 = 0 −3 − 8y = 0 −8y = 3 y = − 3 8 Finally, plug this solution for y into the equation for x x = − 2 − 2y x = − 2 − 2(− 3. Breaking the biggest stories in celebrity and entertainment news
Tweets with replies by Chris Mueller (@camueller) | Twitter
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Journalist addresses online release of explicit videos, sharing personal insights and reactions to the incident. Everyone’s preparing for winter — except the people still pretending this war’s going to end by christmas ⚔️ russia grinds forward, inch by inch russia’s army has pushed deeper into southern ukraine, capturing three more settlements in zaporizhzhia under cover of dense fog — a fitting metaphor for how this war drags on. The sentence van has come. is grammatically correct if the noun van is the name of a person
A proper noun is not usually preceded by an article If the noun van' is a common noun, a word for a type of vehicle, the noun should be preceded by the article the when the van is one that is expected, or preceded by the article a when the van is not one that is expected First, find 2 real roots of the transformed equation Next divide them by a to get the 2 real root of the original equation
Chris Mueller (@ChrisDMueller) | Twitter
Therefore, the 2 real roots of f'(z) are
(3.667,1.5) put both equations in the same graph The point where they intersect at (3.667,1.5) is the solution to the system of equations. What is the strength of the field between the two plates Friction and other factors will always prevent this to be 100% efficient, all input energy would need to be converted in to useful output energy
In any real engine, there will always be friction (since there will always be moving parts) so the engine can never be 100% efficient as energy will be used to overcome the friction (work will be done)
Tweets with replies by Chris Mueller (@camueller) | Twitter
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